The relationship between energy $(E)$ of wavelengths $2000 ˚ A$ and $8000 ˚ A$ , respectively is:

E_{1} = 4 E_{2}

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E_{1} = 2 E_{2}

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E_{1} = \frac{E_{2}}{2}

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E_{1} = \frac{E_{2}}{4}

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Solution

The correct option is A $E_{1} = 4 E_{2}$
According to Planck's theory.
$E = \frac{h c}{λ}$ ,
$\frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}}$
$(∵ E \propto \frac{1}{λ})$

Thus, $\frac{E_{1}}{E_{2}} = \frac{8000}{2000} = 4$

$∴ E_{1} = 4 E_{2}$ .

Hence, option $A$ is correct.

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The relationship between energy (E) of wavelengths 2000˚A and 8000˚A, respectively is:

The correct option is A E1=4E2According to Planck's theory.E=hcλ, E1E2=λ2λ1 (∵E∝1λ)Thus, E1E2=80002000=4∴E1=4E2.Hence, option A is correct.

The relationship between energy $(E)$ of wavelengths $2000 ˚ A$ and $8000 ˚ A$ , respectively is:

The correct option is A $E_{1} = 4 E_{2}$
According to Planck's theory.
$E = \frac{h c}{λ}$ ,
$\frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}}$
$(∵ E \propto \frac{1}{λ})$

Thus, $\frac{E_{1}}{E_{2}} = \frac{8000}{2000} = 4$

$∴ E_{1} = 4 E_{2}$ .

Hence, option $A$ is correct.