The relationship between force and position is shown in the figure (in one dimensional case). Work done by the force in displacing a body from x $=$ 1 cm to x $=$ 5cm is :

700 erg

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70 erg

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60 erg

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20 erg

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Solution

The correct option is C 20 erg
Referring figure,
Work done by the force = $W_{1} + W_{2} + W_{3} + W_{4}$
Where, $W_{1} = a r e a A B C M = 1 \times 10 = 10 e r g$
$W_{2} = a r e a M D E F = 1 \times 20 = 20 e r g$
$W_{3} = a r e a F G H I = 1 \times (- 20) = - 20 e r g$
$W_{4} = a r e a I J K L = 1 \times 10 = 10 e r g$
$∴$ Net work done $= 10 + 20 - 20 + 10 = 20 e r g$

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