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Byju's Answer
Standard XI
Chemistry
Mole Fraction
The relations...
Question
The relationship between molality (m) and mole fraction
(
χ
A
)
of the solvent is:
A
m
=
1
−
X
A
X
A
×
1000
M
A
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B
m
=
X
A
1
−
X
A
×
1000
X
A
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C
m
=
X
A
1
−
X
A
×
1000
X
B
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D
m
=
1
−
X
A
X
A
×
1000
X
B
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Solution
The correct option is
A
m
=
1
−
X
A
X
A
×
1000
M
A
Mole fraction of solute,
X
B
=
n
B
n
A
+
n
B
Molality= m
=
n
B
W
A
(
g
)
×
1000
=
n
B
n
A
M
A
×
1000
⇒
n
B
n
A
=
X
B
X
A
=
(
1
−
X
A
)
X
A
⇒
m
=
1
−
X
A
X
A
×
1000
M
A
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0
Similar questions
Q.
The relationship between molality (m) and mole fraction
(
χ
A
)
of the solvent is:
Q.
The relationship between molality (m) and mole fraction
(
χ
A
)
of the solvent is:
Q.
Molality: It is defined as the number of moles of the solute present in 1 kg of the solvent. It is denoted by 'm'
Molality (m) =
N
u
m
b
e
r
o
f
m
o
l
e
s
o
f
s
o
l
u
t
e
N
u
m
b
e
r
o
f
k
i
l
o
g
r
a
m
s
o
f
t
h
e
s
o
l
v
e
n
t
Let
w
A
grams of the solute of molecular mass
m
A
be present in
w
B
grams of the solvent, then
Molality (m) =
w
A
m
A
×
w
B
×
1000
Relation between mole fraction and Molality :
X
A
=
n
N
+
n
a
n
d
X
B
=
N
N
+
n
X
A
X
B
=
n
N
=
M
o
l
e
s
o
f
s
o
l
u
t
e
M
o
l
e
s
o
f
s
o
l
v
e
n
t
=
W
A
×
m
B
w
B
×
m
A
X
A
×
1000
X
B
×
m
B
=
w
A
×
1000
W
B
×
m
A
=
m
, or,
X
A
×
1000
(
1
−
X
A
)
m
B
=
m
If the ratio of the mole fraction of a solute is changed from
1
3
to
1
2
in the
800
g of solvent then, the ratio of molality will be :
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