The relationship between Young's Modulus E, Modulus of Rigidity C and Bulk Modulus K in an elastic material is given by the relation

E = \frac{9 K C}{3 K + C}

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E = \frac{3 K C}{3 K + C}

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E = \frac{9 K C}{9 K + C}

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E = \frac{3 K C}{9 K + C}

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Solution

The correct option is A $E = \frac{9 K C}{3 K + C}$
$E = 2 C (1 + μ)$ ... (i)
$E = 3 K (1 - 2 μ)$ ... (ii)
Using (i) and (ii)
$E = \frac{9 k C}{3 k + C}$

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