The relative decrease in the vapour pressure of an aqueous solution containing 2 mol NaCI in 3 mol H2O is 0.5. This solution, on reaction with AgNO3 will form:-
A
1 mol AgCI
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B
0.25 mol AgCI
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C
2 mol AgCI
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D
0.5 mol AgCI
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Solution
The correct option is D0.5 mol AgCI ΔPP∘=0.5=i×nn+N i = 1.25 1.25 = 1 + (2 – 1)α α = 0.25 2 mol of NaCl will produce 0.5 mol of Cl− in solution.