The relative density of a substance is 7, the density of the substance is

7 k g / m^{3}

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7 g / m^{3}

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7 \times 10^{3} g / c m^{3}

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7 g / c m^{3}

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Solution

The correct option is D $7 g / c m^{3}$
R.D. = $\frac{Density of the Substance}{Density of water at 4^{\circ} C}$
7 = $\frac{D_{s}}{1 g / c m^{3}}$
Then the density of the substance is
$D_{s} = 7 g / c m^{3}$

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The relative density of a substance is 7, the density of the substance is

The correct option is D 7 g/cm3R.D. = Density of the SubstanceDensity of water at 4∘ C 7 =Ds1 g/cm3 Then the density of the substance is Ds=7g/cm3

The correct option is D $7 g / c m^{3}$
R.D. = $\frac{Density of the Substance}{Density of water at 4^{\circ} C}$
7 = $\frac{D_{s}}{1 g / c m^{3}}$
Then the density of the substance is
$D_{s} = 7 g / c m^{3}$