Question

The relative density of mercury is 13.6. If the volume of water is ten times the volume of mercury then find the ratio of the mass of mercury to the mass of water.

Answer 1

R.D $=$ 13.6
$R.D=\frac{Densityofmercury}{Densityofwater}$
$13.6=\frac{m_{Hg}}{V_{Hg}}\times \frac{V_{water}}{m_{water}}$
$13.6=\frac{m_{Hg}}{V_{Hg}}\times \frac{10V_{Hg}}{m_{water}}$
$\therefore \frac{m_{Hg}}{m_{water}}=13.6:10$
$=34:25$