Question

The relative density of mercury is $13.6$. Its density in S.I. unit is given as $X\times {10}^{3}kg{m}^{-3}$. Find $X$.

• A. $13$
• B. $14$
• C. $13.6$
• D. $14.6$

Answer 1

The correct option is C $13.6$

$RD=\frac{densityofmercury}{densityofwater}$

$13.6=\frac{densityofmercury}{1gc{m}^{-3}}$

So, Density of mercury in CGS $=13.6gc{m}^{-3}$

So, Density of mercury in SI unit$=\frac{13.6\times 100\times 100\times 100}{1000}kg{m}^{-3}$

$\Rightarrow 13.6\times {10}^{3}kg{m}^{-3}$