Question

The relative density of silver is $10.8$. The density of water is $1000kg{m}^{-3}$. The density of silver is:

• A. $10.8\times {10}^{3}kg{m}^{-3}$
• B. $10.8\times {10}^{2}kg{m}^{-3}$
• C. $10.8\times {10}^{1}kg{m}^{-3}$
• D. $10.8\times {10}^{4}kg{m}^{-3}$

Answer 1

The correct option is A $10.8\times {10}^{3}kg{m}^{-3}$

Given,
Relative density of silver = $10.8$
Density of water $=1000kg{m}^{-3}$

Relative density is defined as the ratio of the density of a substance to the density water.

So, Relative density of silver
$=\frac{Densityofsilver}{Densityofwater}$
$\Rightarrow 10.8=\frac{\text{Density of silver}}{1000}$

$\Rightarrow$Density of silver $=10.8\times {10}^{3}kg{m}^{-3}$
$\therefore$The density of silver is $10.8\times {10}^{3}kg{m}^{-3}$.