The relative energies of molecular orbitals are found to be in increasing order as follows- -1 s -1 s -2 s -2 s - -2 py -2 pz-2 px-2 py -2 pz-2 pxA- For O 2 to N e 2B- For H 2 to N 2C- For H 2 to N e 2D- For N 2 to N e 2

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Standard XII

Chemistry

Molecular Orbital Energy Diagrams

The relative ...

Question

The relative energies of molecular orbitals are found to be in increasing order as follows- $σ (1 s) < σ^{} (1 s) < σ (2 s) < σ^{} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{} (2 p_{y}) π^{} (2 p_{z})] < σ^{*} (2 p_{x})$

For

O_{2}

N e_{2}

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For

H_{2}

N_{2}

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For

H_{2}

N e_{2}

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For

N_{2}

N e_{2}

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Solution

The correct option is B For $H_{2}$ to $N_{2}$
From For $H_{2}$ to $N_{2}$ $s - p$ mixing is observed and hence the orbitals follow the energy order shown above

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Similar questions

Q. The relative energies of molecular orbitals are found to be in increasing order as follows-

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

(i)

The energy of $σ 2 p_{z}$ molecular orbital is greater than $π 2 p_{x} and π 2 p_{y}$ molecular orbitals in nitrogen molecule. Write the complete sequence of energy levels in the increasing order of energy in the molecule. Compare the relative stability and the magnetic behaviour of the following species.

$N_{2}$

(ii) $N_{2}^{+}$

(iii) $N_{2}^{-}$

(iv) $N_{2}^{2 +}$

Q. Which of the following order of energies of molecular orbitals of

N_{2}

is correct?

Q. Which of the following orbitals are in the increasing order of energy.

Q. According to MOT, two atomic orbitals overlap resulting in the formation of molecular orbitals. Number of atomic orbitals overlapping together is equal to the molecular orbital formed. The two atomic orbital thus formed by LCAO (linear combination of atomic orbital) in the same phase or in the different phase are known as bonding and antibonding molecular orbitals respectively. The energy of bonding molecular orbital is lower than that of the pure atomic orbital by an amount

Δ

. This known as the stabilization energy. The energy of antibonding molecular orbital is increased by

Δ^{'}

(destabilization energy).
Which of the following statement(s) is(are) true:

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The relative energies of molecular orbitals are found to be in increasing order as follows- σ(1s)<σ∗(1s)<σ(2s)<σ∗(2s)<[π(2py) π(2pz)]<σ(2px)<[π∗(2py) π∗(2pz)]<σ∗(2px)

The correct option is B For H2 to N2From For H2 to N2 s−p mixing is observed and hence the orbitals follow the energy order shown above

The relative energies of molecular orbitals are found to be in increasing order as follows- $σ (1 s) < σ^{} (1 s) < σ (2 s) < σ^{} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{} (2 p_{y}) π^{} (2 p_{z})] < σ^{*} (2 p_{x})$

The correct option is B For $H_{2}$ to $N_{2}$
From For $H_{2}$ to $N_{2}$ $s - p$ mixing is observed and hence the orbitals follow the energy order shown above