Question

The relative energies of molecular orbitals are found to be in increasing order as follows- $\sigma \left(1s\right)<{\sigma }^{\ast }\left(1s\right)<\sigma \left(2s\right)<{\sigma }^{\ast }\left(2s\right)<\left[\pi \right(2p_y\left)\pi \right(2p_z\left)\right]<\sigma \left(2p_x\right)<\left[{\pi }^{\ast }\right(2p_y\left){\pi }^{\ast }\right(2p_z\left)\right]<{\sigma }^{\ast }\left(2p_x\right)$

• A. For $O_2$ to $N{e}_2$
• B. For $H_2$ to $N_2$
• C. For $H_2$ to $N{e}_2$
• D. For $N_2$ to $N{e}_2$

Answer 1

The correct option is B For $H_2$ to $N_2$

From For $H_2$ to $N_2$ $s-p$ mixing is observed and hence the orbitals follow the energy order shown above