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Question

The relative energies of molecular orbitals are found to be in increasing order as follows- σ(1s)<σ(1s)<σ(2s)<σ(2s)<[π(2py) π(2pz)]<σ(2px)<[π(2py) π(2pz)]<σ(2px)
  1. For O2 to Ne2
  2. For H2 to N2
  3. For H2 to Ne2
  4. For N2 to Ne2


Solution

The correct option is B For H2 to N2
From For H2 to N2 sp mixing is observed and hence the orbitals follow the energy order shown above

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