The relative humidity on a day when partial pressure of water vapour is 0-012- 105 Pa at 12-C isTake vapour pressure of water at this temperature as 0-016- 105Pa-

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Standard X

Physics

Relative Humidity

The relative ...

Question

The relative humidity on a day when partial pressure of water vapour is $0.012 \times 10^{5} P a$ at $12^{\circ} C$ is
(Take vapour pressure of water at this temperature as $0.016 \times 10^{5} P a)$ .

70

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40

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75

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25

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Solution

The correct option is B $75$ %
Relative humidity at a given temperature $(R)$
$= \frac{Partial pressure of water pressure}{Vapour pressure of water}$
$= \frac{0.012 \times 10^{5}}{0.016 \times 10^{5}} = 0.75 = 75$ %.

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The relative humidity on a day when partial pressure of water vapour is 0.012×105Pa at 12∘C is(Take vapour pressure of water at this temperature as 0.016×105Pa).

The correct option is B 75%Relative humidity at a given temperature (R)=Partial pressure of water pressureVapour pressure of water=0.012×1050.016×105=0.75=75%.

The relative humidity on a day when partial pressure of water vapour is $0.012 \times 10^{5} P a$ at $12^{\circ} C$ is
(Take vapour pressure of water at this temperature as $0.016 \times 10^{5} P a)$ .

The correct option is B $75$ %
Relative humidity at a given temperature $(R)$
$= \frac{Partial pressure of water pressure}{Vapour pressure of water}$
$= \frac{0.012 \times 10^{5}}{0.016 \times 10^{5}} = 0.75 = 75$ %.