The relative humidity on a day when partial pressure of water vapour is 0-012 - 105 Pa at 12oC is Take vapour pressure of water at this temperature as 0-016 - 105 Pa

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Standard X

Physics

Relative Humidity

The relative ...

Question

The relative humidity on a day when partial pressure of water vapour is $0.012 \times 10^{5} P a$ at $12^{o} C$ is (Take vapour pressure of water at this temperature as $0.016 \times 10^{5}$ Pa)

70%

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40%

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75%

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25%

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Solution

The correct option is C 75%
Given,
Partial pressure of water vapour $= {0.125 \times 10}^{5}$ Pa
Vapour pressure of water $= {0.016 \times 10}^{5}$ Pa
Relative humidity at a given temperature (R)
$= \frac{P a r t i a l p r e s s u r e o f w a t e r v a p o u r}{v a p o u r p r e s s u r e o f w a t e r} = \frac{{0.125 \times 10}^{5}}{{0.016 \times 10}^{5}} = 0.75 = 75$

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The relative humidity on a day when partial pressure of water vapour is 0.012×105Pa at 12oC is (Take vapour pressure of water at this temperature as 0.016×105 Pa)

The correct option is C 75%Given,Partial pressure of water vapour =0.125×105 PaVapour pressure of water=0.016×105 PaRelative humidity at a given temperature (R) =Partialpressureofwatervapourvapourpressureofwater=0.125×1050.016×105=0.75=75

The relative humidity on a day when partial pressure of water vapour is $0.012 \times 10^{5} P a$ at $12^{o} C$ is (Take vapour pressure of water at this temperature as $0.016 \times 10^{5}$ Pa)