Question

The relative number of atoms of different elements in a compound are as follows: $A=$ $1.33$, $B=$ $1$ and $C$ $=$ $1.5$. The empirical formula of the compound is:

• A. $A_2{B}_2{C}_3$
• B. $ABC$
• C. $A_8{B}_6{C}_9$
• D. $A_3{B}_3{C}_4$

Answer 1

Answer: (C)

$A_8{B}_6{C}_9$

Given,

$A:B:C=1.33:1:1.5$

Making it in a simple whole-number ratio by multiplying it with 6, we get-

$=8:6:9$

$⟹\text{Empirical Formula}=A_8{B}_6{C}_9$

Hence, option C is correct.