The relative rates of mononitration of R - C 6 H 5- where R - CH 3- NO 2- OH - Cl areA- H 3 C - C 6 H 5- OH - C 6 H 5- O 2 N - C 6 H 5- Cl - C 6 H 5- OH - C 6 H 5- Cl - C 6 H 5- H 3 C - C 6 H 5- O 2 N - C 6 H 5C- OH - C 6 H 5- CH 3- C 6 H 5- O 2 N - C 6 H 5- Cl - C 6 H 5D- OH - C 6 H 5- H 3 C - C 6 H 5- Cl - C 6 H 5- O 2 N - C 6 H 5

The correct option is D OH C_6H_5 gt;H_3C C_6H_5 gt;Cl C_6H_5 gt;O_2N C_6H_5 CH_3, OH, Cl are ortho para directing groups and shows +M effect. But N ...

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Standard XII

Chemistry

Aromatic Directive Influence

The relative ...

Question

The relative rates of mononitration of $R - C_{6} H_{5},$ where $R = - C H_{3}, - N O_{2}, - O H, - C l$ are

H_{3} C - C_{6} H_{5} > O H - C_{6} H_{5} > O_{2} N - C_{6} H_{5} > C l - C_{6} H_{5}

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O H - C_{6} H_{5} > C l - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > O_{2} N - C_{6} H_{5}

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O H - C_{6} H_{5} > C H_{3} - C_{6} H_{5} > O_{2} N - C_{6} H_{5} > C l - C_{6} H_{5}

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O H - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > C l - C_{6} H_{5} > O_{2} N - C_{6} H_{5}

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Solution

The correct option is D $O H - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > C l - C_{6} H_{5} > O_{2} N - C_{6} H_{5}$
$- C H_{3}, - O H, - C l$ are ortho-para directing groups and shows +M effect. But $- N O_{2}$ is meta directing group and deactivates the ring and makes the ring difficult for electrophilic substitution reaction.
$- O H$ is strong ring activating group followed by $- C H_{3}$ and $- C l$ .
The relative rates of mononitration is $O H - C_{6} H_{5} > H_{3} C - C_{6} H_{5} > C l - C_{6} H_{5} > O_{2} N - C_{6} H_{5}$

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Similar questions

Q. The relative rates of mononitration of

R - C_{6} H_{5},

where

R = - C H_{3}, - N O_{2}, - O H, - C l

are

Q. In the given reaction
$C_{6} H_{5} - O | | C - O | | C - C_{6} H_{5} \frac{(i) C H_{3} M g B r (e x c e s s)}{(i i i) H O H / H^{@}} P r o d u c t$

Product will be:

$(a) C_{6} H_{5} C - O H | C | C H_{3} - O H | C | C H_{3} - C_{6} H_{5}$

$(b) C_{6} H_{5} C - O H | C | C H_{3} - O | C - C_{6} H_{5}$
$(c) C_{6} H_{5} - C O O H$
$(d) C_{6} H_{5} - C H O H - C H O H - C_{6} H_{5}$

Identify (W)

Q. In the given reaction
$C_{6} H_{5} - C H_{3} \to \frac{a i r / M n (I I) / C u (I I)}{△} [X]$
[X] is:
$(a) C_{6} H_{5} - C H O (b) C_{6} H_{5} - C O O H$
$(c) C_{6} H_{5} - C H_{2} O H (d) C_{6} H_{5} - O H$

Q. Consider the following Carbocations :
I)

C_{6} H_{5} \leftarrow C H_{2}

II)

C_{6} H_{5} \leftarrow C H_{2} C H_{2}

III)

C_{6} H_{5} \leftarrow C H \leftarrow C H_{3}

IV)

C_{6} H_{5} \leftarrow C (C H_{3})_{2}

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Aromatic Directive Influence

Standard XII Chemistry

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The relative rates of mononitration of R−C6H5, where R=−CH3,−NO2,−OH,−Cl are

The relative rates of mononitration of $R - C_{6} H_{5},$ where $R = - C H_{3}, - N O_{2}, - O H, - C l$ are