Question

The relative reactivity of $1^{o}H,2^{o}H$ and $3^{o}H$ in bromination reaction has been found to be 1 : 82 : 1600 respectively. In the reaction the percentage yields of the products (A) and (B)
are expected to be:

• A. 99.4%, 0.6%
• B. 50%, 50%
• C. 0.6%, 99.4%
• D. 80%, 20%

Answer 1

The correct option is A 99.4%, 0.6%

(a) $9\times 10=9\frac{9}{1600+9}\times 100=0.6$%
(b) $1\times 1600=1600=\frac{1600}{1600+9}\times 100=99.4$%