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Question
The remainder obtained when (1! + 2! + 3! + …..100!) is divided by 10 is
The remainder obtained when (1! + 2! + 3! + …..100!) is divided by 10 is
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Solution
The correct option is D 3
From 5! Onwards the unit digit is zero.
So, 1!+2!+3!+4! = 33
So, the unit digit of (1! + 2! + 3! + …..100!) is 3.
So, the remainder is 3.
3
From 5! Onwards the unit digit is zero.
So, 1!+2!+3!+4! = 33
So, the unit digit of (1! + 2! + 3! + …..100!) is 3.
So, the remainder is 3.
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