The remainder obtained when 1!+2!+3!+4!+5!+…….+99! Is divided by 48 is
0
1
9
47
From 6! It is divisible by 48. So when, 1!+2!+3!+4!+5! = 153 is divided by 48 the remainder is 9.
The remainder obtained when 1!+2!+3! ……+11! Is divided by 12 is …….
The remainder obtained when (11+22+33+44+55+…1010) is divided by 4 is