The remainder obtained when (1! + 2! + 3! + …..50!) is divided by 15 is

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Solution

The correct option is B
3

(1! + 2! + 3! + …..50!) = 1+2+6+24+15k (where k is an integer)

So the remainder when (1! + 2! + 3! + …..50!)is divided by 15 is 3.

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