Question

The remainder obtained when ${2003}^{96}$ is divided by 10 is

• A. 0
• B. 1
• C. 2
• D. 9

Answer 1

The correct option is B

1

$(2003{)}^{96}={(2000+3)}^{96}$
= $2000k+3^{96}$, where k is an integer ( using binomial theorem )
The unit digit in $3^{96}$ is 1, so the remainder obtained when ${2003}^{96}$ is divided by 10 is 1.