The remainder obtained when $23^{21} - 19^{21}$ is divisible by 21 is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
16

$23^{21} - 19^{21} = 21 k + 2^{22}$ , where k is an integer.
The remainder obtained when $2^{22}$ is divided by 21 is 16.

Suggest Corrections

Similar questions

Q. Find the remainder obtained when

x^{2007}

is divisible by

x^{2} - 1

Q. In a division sum, the remainder is

0

when a student mistook the divisor by

12

instead of

21

and obtained

35

as quotient. What is the correct quotient?

Q. The remainder obtained when the polynomial

1 + x + x^{3} + x^{9} + x^{27} + x^{81} + x^{243}

is divisible by

x - 1

The remainder obtained when the sum of first 21 natural numbers is divided by 8 is

An unknown polynomial yields a reminder 2 upon division by x-1, and remainder 1 upon division by x-2. What remainder is obtained if this polynomial is divided by {x-1}{x-2}.

Join BYJU'S Learning Program

The remainder obtained when 2321−1921 is divisible by 21 is

The correct option is D 16 2321−1921=21k+222, where k is an integer. The remainder obtained when 222 is divided by 21 is 16.

The remainder obtained when $23^{21} - 19^{21}$ is divisible by 21 is

The correct option is D
16

$23^{21} - 19^{21} = 21 k + 2^{22}$ , where k is an integer.
The remainder obtained when $2^{22}$ is divided by 21 is 16.