The remainder obtained when 5150+4950is divided by 50 is
0
49
1
2
5150 = (50+1)50
4950 = (50−1)50
5150+4950 = (50+1)50+(50−1)50
= 50k + 2 (using binomial theorem)
So when this is divided by 50 the remainder is 2.
The remainder obtained when 9722 is divided by 1001 is
The remainder obtained when (1! + 2! + 3! + …..50!) is divided by 15 is
The remainder obtained when 9696 is divided by 7 is