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Question

The remainder obtained when (11+22+33+44+55+1010) is divided by 4 is


A

0

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B

1

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C

2

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D

3

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Solution

The correct option is B

1


remainders obtained dividing every term with 4

(11/4=1,22/4=0,33/413/4=1,44/4=0,55/415/4=1)

remainder =1+0+(-1)+0+1+0+(-1)+0+1+0 =1


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