The remainder obtained when (11+22+33+44+55+…1010) is divided by 4 is
0
1
2
3
remainders obtained dividing every term with 4
(11/4=1,22/4=0,33/4⇒−13/4=−1,44/4=0,55/4⇒15/4=1…)
remainder =1+0+(-1)+0+1+0+(-1)+0+1+0 =1
The remainder obtained when 339 + 449 + 439 is divided by 9 is
The remainder obtained when (13+23+33+43+……1003) is divided by 9 is
The remainder obtained when (12+22+32+42+52+…1002) is divided by 7 is: