The remainder obtained when $(103^{7} - 103)$ is divided by 42 is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
0

$(103^{7} - 103)$ = $103 (103^{6} - 1)$

=103 $(103^{3} - 1)$ $(103^{3} + 1)$

= $103 [102 \times 10713 \times 104 \times 10507]$

102 is divisible by 6 and 10507 is divisible by 7

So, the remainder is 0.

Suggest Corrections

Similar questions

The remainder obtained when $(19^{103} + 19^{2})$ is divided by 20 is

9^{103}

25

The remainder obtained when $(1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + \dots 100^{2})$ is divided by 7 is:

The remainder when $7^{103}$ is divided by 25 is:

^{103}

25.

Join BYJU'S Learning Program