The remainder obtained when(19103+192) is divided by 20 is
0
3
11
1
(19103+192)=192(19101+1)(19101+1) is divisible by 20[(xn+1) will be divisible by (x+1) when n is odd.)]
The remainder obtained when 9696 is divided by 7 is
The remainder obtained when 200396 is divided by 10 is
The remainder obtained when 26812681 is divided by 3 is