The remainder obtained when (2+22+23…2100) is divided by 5 is
A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A
0
The unit digit of 2,22,23,24 are 2,4,8,6. For the next four consecutive terms also have same unit digits and so on. So the unit digit of (2+22+23…2100) is 0. So, the remainder is 0.