The remainder obtained when $x^{64} + x^{27} + 1$ is divided by x + 1 is

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-1

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Solution

The correct option is C 1
Here $f (x) = x^{64} + x^{27} + 1$
the remainder when f(x) is divided
by $(x + 1)$ is
$f (- 1)$ from remainder theorem
$f (- 1) = 1$
So, remainder is 1.

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