The remainder obtained when the sum of first 21 natural numbers is divided by 8 is
4
7
6
3
Sum of first 21 natural numbers is 231.
The remainder obtained when it is divided by 8 is 7.
The remainder obtained when the sum of squares first n odd natural numbers is divided the sum of squares of first n even natural numbers is
The remainder obtained when the sum of the first eight terms of the sequence 8, 64, 512, ..... is divided by 9 is
Three consecutive natural numbers are added and their sum is divided by 3. What is the remainder obtained?
In first 1000 natural numbers, how many numbers exists such that when divided by 11 leaves a remainder of 8?