Question

The remainder when $2^2+{22}^2+{222}^2+{2222}^2+....(222....49twos{)}^2$ is divided by 9 is

• A. 2
• B. 5
• C. 6
• D. 7

Answer 1

The correct option is C 6

Looking closely at the remainders individually we get a pattern as follows:
4+7+0+1+1+0+7+4+0 ... It will repeat after every 9 terms ...
5(24) till 45 terms + 4+7+0+1 =132
132/9=6
Hence, 6 is the remainder.