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B
2
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C
8
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D
11
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Solution
The correct option is C8 22003=23×22000=8(24)500=8(16)500=8(17−1)500=8[500C0⋅17500−500C1⋅17499+…+500C500]=8[17k+1],k∈N=17×8k+8
Hence, the remainder is 8.