The remainder when 32015 is divided by 22 is
We have
32015
Then,
32015=34×503+3
=34×503+33
The remainder when 1+21+22+23............21999 is divided by 5 is:
The remainder obtained when (2+22+23…2100) is divided by 5 is
The remainder obtained when (12+22+32+42+52+…1002) is divided by 7 is: