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Quantitative Aptitude

Divisibility Rule for Composite Numbers

The remainder...

Question

The remainder when $9^{19} + 6$ is divides by $8$ , is

2

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3

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5

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7

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Solution

The correct option is D $7$
$9 \equiv 1$ (mod 8)
$9^{19} \equiv 1^{19}$ (mod 8)
$9^{19} \equiv 1$ (mod 8)
$9^{19} + 6 \equiv 7$ (mod 8)
7 is the remainder when $9^{19} + 6$ is
divided by 8.

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The remainder when 919+6 is divides by 8, is

The correct option is D 79≡1 (mod 8)919≡119 (mod 8)919≡1 (mod 8)919+6≡7 (mod 8) 7 is the remainder when 919+6 is divided by 8.

The remainder when $9^{19} + 6$ is divides by $8$ , is

The correct option is D $7$
$9 \equiv 1$ (mod 8)
$9^{19} \equiv 1^{19}$ (mod 8)
$9^{19} \equiv 1$ (mod 8)
$9^{19} + 6 \equiv 7$ (mod 8)
7 is the remainder when $9^{19} + 6$ is
divided by 8.