The remainder when $x^{3} - 2 x^{2} + 4 x$ is divided by $x^{2}$ is

1

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x - 2 + \frac{4}{x}

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4 x

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4 x - 2 x^{2}

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Solution

The correct option is C $4 x$
$x^{3} - 2 x^{2} + 4 x = x^{2} (x - 2) + 4 x =$
so when divided by $x^{2}$ reminder is $4 x$

Suggest Corrections

Similar questions

x^{3} + 2 x^{2} + 4 x + 3

x - 1

What is the quotient when $x^{3} + 2 x^{2} - 3$ is divided by x – 2?

p (x)

g (x)

p (x) = x^{3} - 2 x^{2} - 4 x - 1

g (x) = x + 1

f (x) = 2 x^{2} - 4 x + 2

g (x) = x - 2

x^{3} - 2 x^{2} - 4 x - 1

x - 1

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