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Byju's Answer

Standard VIII

Mathematics

Visualising Powers and Exponents

The remainder...

Question

The remainder when ${(32^{12})}^{32}$ is divided by $7$ is

2

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4

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6

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Solution

The correct option is B $2$
${({(32)}^{12})}^{32} {(2^{60})}^{32} 2^{1920}$
When $2^{4}$ divides by $7$ given remainder $2.$
Hence when $2^{1920}$ divides by given remainder $2.$

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The remainder when (3212)32 is divided by 7 is

The correct option is B 2((32)12)32(260)3221920When 24 divides by 7 given remainder 2.Hence when 21920 divides by given remainder 2.

The remainder when ${(32^{12})}^{32}$ is divided by $7$ is

The correct option is B $2$
${({(32)}^{12})}^{32} {(2^{60})}^{32} 2^{1920}$
When $2^{4}$ divides by $7$ given remainder $2.$
Hence when $2^{1920}$ divides by given remainder $2.$