Question

The remainder when $n^2-6n-50(n\in N)$ is divided by $36$, is:

• A. $22$
• B. $23$
• C. $1$
• D. $21$

Answer 1

The correct option is A $22$

We use the equation $f\left(n\right)=n^2-6n-50$.

Using the Remainder theorem,

Remainder $=f\left(36\right)={36}^2-6\left(36\right)-50=1296-216-50=1030$.

Since remainder can't be greater than the divisor, we'll further divide $1030$ to get a remainder less than the divisor.

Remainder on dividing $1030$ by $36$ is $22$ .

Therefore, the remainder obtained is $22$.

Hence, option $A$ is correct.