The remainder when polynomial x3−ax2+6x−a is divided by (x−1) is
7 – 2a
7
7 - a
7 - 8a
Let p(x)=x3−ax2+6x−a. If p(x) is divided by (x-1), then remainder is p(1). p(1)=(1)3−a(1)2+6(1)−a =1−a+6−a=7−2a.
When the polynomial x3+2x2−5ax−7 is divided by (x−1), the remainder is A and when the polynomial x3+ax2−12x+16 is divided by (x+2), the remainder is B. Find the value of 'a' if 2A+B=0.
Find the remainder when x3−ax2+6x−a is divided by x−a.