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Question

The remainder when the polynomial p(x)=x100x97+x3 is divided by x+1 is

A
1
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B
22
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C
3
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D
4
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Solution

The correct option is C 1
Here, p(x)=x100x97+x3,

To check the remainder obtained when p(x) is divided by x+1, equate x+1 to 0 and put that value of x in p(x).

x+1=0x=1

So,
p(1)=(1)100(1)97+(1)3
=1+11
=1
So, by the Remainder Theorem 1 is the remainder when x100x97+x3 is divided by x+1.

Option A is correct.

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