The remainder when x101+101 is divided by x+1 is:
100
101
102
103
According to a rule: P(x)(x−a) leaves the remainder as P(a).
x101+101(x+1) = P(-1) = - 1 + 101 = 100
When N is divided by X, the remainder is 28. When N is divided by 10X, the remainder is 125. Find the remainder when N is divided by 5X.
The remainder obtained when (1037−103)is divided by 42 is
The remainder obtained when(104303) is divided by 101 is
The remainder when 7103 is divided by 25 is: