Question

The remainder when $x^3+4x^2-7x+6$ is divided by $(x-1)$ is

• A. $4$
• B. $0$
• C. $-4$
• D. $3$

Answer 1

The correct option is A $4$

Let $f\left(x\right)=x^3+4x^2-7x+6$
As $f\left(x\right)$ is divided by $x-1$, substituting $x=1$ in $f\left(x\right)$ we get
$f\left(1\right)=1^3+4\cdot 1^2-7\cdot 1+6=4$
Hence, $4$ is the remainder.