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Remainder Theorem

The remainder...

Question

The remainder when $x^{3} + 4 x^{2} - 7 x + 6$ is divided by $(x - 1)$ is

4

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0

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- 4

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3

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Solution

The correct option is A $4$
Let $f (x) = x^{3} + 4 x^{2} - 7 x + 6$
As $f (x)$ is divided by $x - 1$ , substituting $x = 1$ in $f (x)$ we get
$f (1) = 1^{3} + 4 \cdot 1^{2} - 7 \cdot 1 + 6 = 4$
Hence, $4$ is the remainder.

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