The remainder when $x^{3} - 6 x^{2} + 11 x - 6$ is divided by $x + 2$ is

- 60

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- 39

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31

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45

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Solution

The correct option is A $- 60$
Given $f (x) = x^{3} - 6 x^{2} + 11 x - 6$
Divisor is $(x + 2)$
$\Rightarrow a = - 2$
Therefore, according to remainder theorem
$R = f (a)$
$= f (- 2)$
$= (- 2)^{3} - 6 (- 2)^{2} + 11 (- 2) - 6$
$= - 60$

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