The repeated root of $x^{3} + 4 x^{2} + 5 x + 2 = 0$ is

-5/3

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-2

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-1

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Solution

The correct option is C -1
$x^{3} + 4 x^{2} + 5 x + 2 = (x + 1) (x^{2} + 3 x + 2)$

$= (x + 1) (x + 1) (x + 2)$

$x^{3} + 4 x^{2} + 5 x + 2 = (x + 1)^{2} (x + 2)$

The repeated root is $- 1$

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