The representation of $l_{1} parallel to l_{2}$ and $l_{3} perpendicular to l_{2}$ is respectively .

l_{1} ∥ l_{2}, l_{3} ⊥ l_{2}

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l_{1} ⊥ l_{2}, l_{3} ∥ l_{4}

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l_{1} ⊥ l_{2}, l_{3} ⊥ l_{4}

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Solution

The correct option is A $l_{1} ∥ l_{2}, l_{3} ⊥ l_{2}$
Perpendicular is representated as - $⊥$
Parallel is representated as - $∥$

So, $l_{1} ∥ l_{2}$ ; $l_{3} ⊥ l_{2}$

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Similar questions

l_{1} parallel to l_{2}

l_{3} perpendicular to l_{2}

The representation of $l_{1} parallel to l_{2}$ and $l_{3} perpendicular to l_{2}$ is respectively,

Match the equations A, B, C, D with the lines L₁, L₂, L₃, L₄, L₅ whose graphs are roughly drawn in the adjoining figure.

A: y = 2

B: y – 2 + 2 = 0

C: 3 + 2y = 6

D: y = -2

E : = 2

l_{1} ⊥ l_{2}

l_{2} ⊥ l_{3}

l_{1}

l_{3}

y^{2} = 4 a x

l_{1}, l_{2} . l_{3}

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