The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and 0.002768Scm−1, respectively. When filled with 0.005NK2SO4, the solution had a resistance of 324 ohm. Cell constant is
A
0.228cm−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.728cm−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.528cm−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.428cm−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A0.228cm−1 k=1R×1a ∴1a(constant)=k×R=0.002768×82.4=0.2281cm−1