The resistance between points M and N in the circuit isA- 4 -48 -24 -D- 64 -

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Standard XII

Physics

Kirchhoff's Junction Law

The resistanc...

Question

The resistance between points $M$ and $N$ in the circuit is

24 Ω

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48 Ω

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64 Ω

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4 Ω

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Solution

The correct option is B $48 Ω$

$R_{2}, R_{3}$ in series $R^{'} = R_{2} + R_{3} = 32 Ω$

$R_{5}, R_{6}$ in series $R "= R_{5} + R_{6} = 32 Ω$

$R^{'}, R^{''}$ are in parallel, $R^{'''} = 16 Ω$

$R_{1}$ , $R_{4}$ and $R^{'} "$ are in series $= R_{1} + R^{'''} + R_{4}$

$16 + 16 + 16 = 48 Ω$

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The resistance between points M and N in the circuit is

The correct option is B 48 Ω R2,R3 in series R′=R2+R3=32 Ω R5,R6 in series R"=R5+R6=32 Ω R′,R′′ are in parallel, R′′′=16 Ω R1, R4 and R′" are in series =R1+R′′′+R4 16+16+16=48 Ω

The resistance between points $M$ and $N$ in the circuit is

The correct option is B $48 Ω$

$R_{2}, R_{3}$ in series $R^{'} = R_{2} + R_{3} = 32 Ω$

$R_{5}, R_{6}$ in series $R "= R_{5} + R_{6} = 32 Ω$

$R^{'}, R^{''}$ are in parallel, $R^{'''} = 16 Ω$

$R_{1}$ , $R_{4}$ and $R^{'} "$ are in series $= R_{1} + R^{'''} + R_{4}$

$16 + 16 + 16 = 48 Ω$