The correct option is B (1+√3)
Let the equivalent resistance between A and B be R then since it is extending to infinity, equivalent resistance between C and D is also R ( The circuit appears the same when seen from C-D and when seen from A-B due to the infinite number of similar branches).
Equivalent resistance across AB will be
∴ RAB=1+RR+1+1=R
R+2(R+1)R+1=R
2+3R=R2+R
R2−2R−2=0
R=2±√4+82
R=√3+1,1−√3
(Negative value of resistance is not possible)
Thus, equivalent resistance between A and B is (√3+1)Ω
Hence, option (c) is correct.