You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Oxidation and Reduction

The resistanc...

Question

The resistance of 1 N solution of acetic acid is 250 ohm, when measured in a cell of cell constant 1.15 $c m^{- 1}$ . The equivalent conductance (in $o h m^{- 1} c m^{2} e q^{- 1}$ ) of 1 N acetic acid is:

4.6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.023

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4.6$
As we know,
K $= \frac{1}{R} \times G * = G \times G * = \frac{1}{250} \times 1.15 = 0.0046 S C m^{- 1}$

Now,
$Λ_{e q} = \frac{k \times 1000}{N} = \frac{0.0046 \times 1000}{1} = 4.6 o h m^{- 1} c m^{2} e q^{- 1}$

Suggest Corrections

Similar questions

The resistance of $1 N$ solution of acetic acid is $250 o h m .$ when measured in a cell of cell constant $1.15$ $c m^{- 1}$ . The equivalent conductance of $1 N$ acetic acid (in $o h m^{- 1}$ $c m^{2}$ $e q v^{- 1}$ ) is:

Q. The resistance of

1 N

solution of acetic acid is

250 o h m

, when measured in a cell having a cell constant of

1.15 {c m}^{- 1}

. The equivalent conductance (in

{o h m}^{- 1} {c m}^{2} {e q u i v}^{- 1}

) of

1 N

acetic acid is:

Q. The resistance of 1N solution of acetic acid is 250Ω when measured in a cell having a cell constant of 1.15

c m^{- 1}

. The equivalent conduction (in

o h m^{- 1} c m^{2} e q u i v^{- 1}

) of 1N acetic acid is

Q. The resistance of

1 N

solution of acetic acid is

250 Ω

, when measured in a cell having a cell constant of

1.15 {c m}^{- 1}

. The equivalent conductance (in

Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}

) of

1 N

acetic acid is:

Q. The resistance of

1 N

solution of

C H_{3} C O O H

250 o h m

when measured in a cell of cell constant

1.15 c m^{- 1}

. The equivalent conductance will be:

Join BYJU'S Learning Program

The resistance of 1 N solution of acetic acid is 250 ohm, when measured in a cell of cell constant 1.15 cm−1. The equivalent conductance (in ohm−1cm2eq−1) of 1 N acetic acid is:

The correct option is A 4.6As we know,K =1R×G∗=G×G∗=1250×1.15=0.0046SCm−1Now,Λeq=k×1000N=0.0046×10001=4.6ohm−1cm2eq−1

The resistance of 1 N solution of acetic acid is 250 ohm, when measured in a cell of cell constant 1.15 $c m^{- 1}$ . The equivalent conductance (in $o h m^{- 1} c m^{2} e q^{- 1}$ ) of 1 N acetic acid is:

The correct option is A $4.6$
As we know,
K $= \frac{1}{R} \times G * = G \times G * = \frac{1}{250} \times 1.15 = 0.0046 S C m^{- 1}$

Now,
$Λ_{e q} = \frac{k \times 1000}{N} = \frac{0.0046 \times 1000}{1} = 4.6 o h m^{- 1} c m^{2} e q^{- 1}$