The resistance of 100 m long copper wire with diameter 1 mm is = ___ ohms.

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Solution

Using the relationship,

R = ρ $\frac{L}{A}$

We have,

R = $\frac{1.6 \times 10^{- 6} \times 100}{3.141 \times {0.5 \times 0.001}^{2}}$

= 2.04 ohms

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The resistance of 100 m long copper wire with diameter 1 mm is = ___ ohms.

Using the relationship, R = ρLA We have, R = 1.6× 10−6× 1003.141× 0.5× 0.0012 = 2.04 ohms

Using the relationship,

R = ρ $\frac{L}{A}$

We have,

R = $\frac{1.6 \times 10^{- 6} \times 100}{3.141 \times {0.5 \times 0.001}^{2}}$

= 2.04 ohms