The resistance of $1 N$ solution of acetic acid is $250 Ω$ , when measured in a cell having a cell constant of $1.15 {c m}^{- 1}$ . The equivalent conductance (in $Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}$ ) of $1 N$ acetic acid is:

2.3

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9.2

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Solution

The correct option is B $4.6$
Equivalent conductivity $(Λ_{e q}) = \frac{κ \times 1000}{N}$

$κ = \frac{c e l l c o n s t a n t}{r e s i s t a n c e} = \frac{1.15}{250} S {c m}^{- 1}$

$∴ (Λ_{e q}) = \frac{1.15 \times 1000}{250 \times 1} = 4.6 Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}$

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The resistance of 1N solution of acetic acid is 250Ω, when measured in a cell having a cell constant of 1.15cm−1. The equivalent conductance (in Ω−1cm2equiv−1) of 1N acetic acid is:

The correct option is B 4.6Equivalent conductivity (Λeq)=κ×1000Nκ=cellconstantresistance=1.15250 Scm−1∴(Λeq)=1.15×1000250×1=4.6 Ω−1cm2equiv−1

The resistance of $1 N$ solution of acetic acid is $250 Ω$ , when measured in a cell having a cell constant of $1.15 {c m}^{- 1}$ . The equivalent conductance (in $Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}$ ) of $1 N$ acetic acid is:

The correct option is B $4.6$
Equivalent conductivity $(Λ_{e q}) = \frac{κ \times 1000}{N}$

$κ = \frac{c e l l c o n s t a n t}{r e s i s t a n c e} = \frac{1.15}{250} S {c m}^{- 1}$

$∴ (Λ_{e q}) = \frac{1.15 \times 1000}{250 \times 1} = 4.6 Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}$